A does half as much work as B in one third of the time taken byB.if together they take 10 days to complete a work then the time taken by B alone to do it is
Let the time taken by "B" be 'x' days.
Time taken by "A" to do (1/2) work = x/3 days.
.'. Time taken by "A" to do full work = 2x/3 days.
Together they take 10 days .
i.e (A+B) tgthr = [(A * B)/ (A + B) ] = 10.
[ x*(2x/3) / (x + 2x/3) ] = 10 .
[(2x^2/3) / (5x/3) ] = 10 .
2x / 5 = 10 .
x = 10*5 / 2
= 25 days .
Then no of days taken by B=25/3*3=25
Need explanation sreekanth