An aqueous solution of Glucose boils at 100.01C ,molal elevation constant of water is 0.5 K .How many molecules of Glucose are present in 100 grams of water?
We know that
elevation in bp=k*(moles of solute÷mass of solvent)*vant off factor (1 for glucose)*1000
0.01=moles of glucose*10*0.5
Moles of glucose 0.002
Ie 1.2 ×10^21 molecules
Please tell me method
1.2×10^21 molecules of sugar feel free to ask if u want method