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Question 1

Evaluate: .

Solution:


 

Question 2

Evaluate .


Solution:



Question 3

Evaluate .


Solution:

Question 4

.

Solution:



Question 5

Simplify .


Solution:



Question 6

Solve the following equation & find the value of m in.


Solution:



Question 7

Solve the following equation & find the value of m in.


Solution:



Question 8

Solve the following equation & find the value of m in.


Solution:



Question 9

Find the value of.


Solution:



Question 10

Find the value of .


Solution:



Question 11

Find the value of .

Solution:



Question 12

Evaluate .


Solution:



Question 13

Evaluate .


Solution:



Question 14

Show that .

Solution:



Question 15

Simplify .


Solution:



Question 16

If .


Solution:



Question 17

Simplify .


Solution:



Question 18

Simplify: .


Solution:



Question 19

Simplify: .

Solution:



Question 20

Express as a power of 3 in 729 and 343.


Solution:



Question 21

Simplify .


Solution:



Question 22

Express the following numbers in usual form.


Solution:


Question 23


 
Express the number appearing in the following statements in standard form.

Solution:

(i) Thickness of a chart paper is 0.05 mm.

(ii) Change of an electron is 0.000,000,000,000,000,00012 wool amb.

Answer:

(i) Thickness of a chart paper is 0.05 mm.

Standard form of thickness of chart paper = 5 × 10-2 mm

(ii) Change of an electron is 0.000,000,000,000,000,00012 wool amb.

Change of electron

Question 24

Express the following number in standard form.


Solution:



Question 25

simplify:.

Solution:



Question 26

Simplify .

Solution:



Question 27

Simplify.


Solution:



Question 28

In a library, there are 6 books each of thickness 30mm and 6 paper sheets each of thickness 0.018mm. What is the total thickness?


Solution:

Thickness of one book = 30mm

Thickness of 6 books = 30 × 6 = 18mm -------(1)

Thickness of one paper = 0.018

Thickness of 6 papers = 6 × 0.018 = 0.108 ----(2)

+ (2) 18 + 0.108 = 18.108 mm

Total thickness = 18.108 mm

Question 29

Solve .

 


Solution:

Equating the powers on both sides,





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