# Area of the Rectangular Path

In our lower classes we have studied how to calculate the area and perimeter of different geometrical shapes. Here is an example where we are going to calculate the area and perimeter of the rectangular path.

Consider, a rectangular park whose length is 40*m* and width 20*m*. Find the perimeter and area of the rectangular park. There is a path of width 1*m* running inside the park which has to be cemented. If one bag of cement is required to cement the area of 8 *sq. m* find the number of bags required to construct the cemented area.

**Solution:**

Given: Length of the rectangular park = 40 *m*

Breadth of the rectangular park = 20* m*

Perimeter of this park

Perimeter of the park = 120 *m*

Area of rectangular park

Area of the rectangular park = 800 *m*^{2}.

Area of the inner rectangular park = (40 - 2)

Ã— (20 - 2) = 38 Ã— 18 = 684Therefore, area of the path = 800 - 684 = 116

*m*

^{2}

1 bag of cement is required to cement 8* m*^{2} .

Number of cemented bags used =

=

Number of bags used to construct the cement area = 14.5 bags

Area of cemented park = Area of park - Area of park which is not cemented

Width of the path = 1*m*

Area of the rectangular park which is not cemented =

Therefore,

Area of cemented path = Area of park - Area of park which is not cemented

= 800 âˆ’ 684 =

Area of the cemented path =

A Swimming pool is in the shape of a rectangle and a circle touching each other. The length of the rectangle is 32 feet. The breadth and the diameter of the circle are the same and is equal to 16 feet. Find the area and perimeter of the swimming pool.