# Solved Problems-4

Problems-4

In the network shown in the figure, the switch

*S*is closed and a steady state is attained. At*t*= 0, the switch is opened. Determine the current through the inductor for*t*> 0.Solution

When the switch

*S*is closed and the steady-state exists, the current through the inductor is,*i*(0 â€“) = = 2 A

The voltage across the capacitor,

*V*(_{C }*t*) = 0 as it is shorted.For

*t*> 0, the switch is opened. By KVL,Taking Laplace transform,

or

Putting the values,

Taking inverse Laplace transform,