Previous Year Paper
CAT-2003-Previous Years Paper
A family has only one kid. The father says “after n years, my age will be 4 times the age of my kids.” The mother says “after n years, my age will be 3 times that of my kid.” What will be the combined ages of the parents after n years?
A- The age difference between the parents is 10 years.
B- After n years, the kid is going to be twice as old as she is now.
|A||if the question can be answered by using statement A alone but not by using B alone.|
|B||if the question can be answered by using statement B alone but not by using A alone.|
|C||if the question can be answered by using either statement alone.|
|D||if the question can be answered by using both the statements together but not by either statement.|
According to the problem, we have:
Let the ages of father, mother and son be F, M and S respectively.
(F + n) = 4 (S + n) and (M + n) = 3(S + n)
Statement A: It gives that F - M = 10, and by subtracting the two equations given above we get, F + n - M - n = 4S - 3S + n = S + n
Gives us that S + n (age of son after n years) is 10 years.
Adding the two above given equations we get F + n + M + n = 7(S + n) = 70. Thus statement A gives us an answer.
Statement B: S + n = 2S, so, S = n. This statement does not give any conclusive answer. Hence, option (a) is the answer.