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Previous Year Paper

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CAT-2006-Previous Years Paper

Question
24 out of 25
 

An equilateral triangle BPC is drawn inside a square ABCD. What is the value of the angle APD in degrees?



A 75
B 90
C 120
D 135
E 150

Ans. E

PBC = CPB = BPC (equilateral triangle) and PC = CD = a.

CPD = PDC = 75o[(180o – 30o)/2]

Similarly, BAP = BPA = 75o

Hence APD = 360o – (75o +75o + 60o) = 150o

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