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CAT-2005-Previous Years Paper
Consider the triangle ABC shown in the following figure where BC = 12 cm, DB = 9 cm, CD = 6 cm and ∠BCD = ∠BAC
What is the ratio of the perimeter of ΔADC to that of the ΔBDC?
Hence, ∠ACB = Θ + [180 – (20 + a] = 180 – (Θ + α)
So, here we can say that the triangle BCD and triangle ABC will be similar ΔBCD ∼ ΔBAC.
Hence, from the property of similarity
Hence, AB = 16
Hence, AC = 8
Hence, AD = 7, AC = 8
SADC = 8 + 7 + 6 = 21
SBDC = 27
Hence, r =