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CAT-2005-Previous Years Paper

Question
23 out of 30
 

Consider the triangle ABC shown in the following figure where BC = 12 cm, DB = 9 cm, CD = 6 cm and BCD = BAC

What is the ratio of the perimeter of ΔADC to that of the ΔBDC?



A 7/9

B 5/9

C 1/3

D 2/3

Ans. A

Hence, ACB = Θ + [180 – (20 + a] = 180 – (Θ + α)

So, here we can say that the triangle BCD and triangle ABC will be similar ΔBCD ΔBAC.

Hence, from the property of similarity

Hence, AB = 16

Hence, AC = 8

Hence, AD = 7, AC = 8

SADC = 8 + 7 + 6 = 21

SBDC = 27

Hence, r =

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