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CAT-2005-Previous Years Paper

Question
10 out of 30
 

For which value of k does the following pair of equations yield a unique solution of x such that the solution is positive?

x2y2 = 0 and (xk)2 + y2 = 1



A 2
B 0

C
D –2

Ans. C

y2= x2

2x2 – 2kx + k2 – 1 = 0

D = 0

4k2 = 8k2 – 6

4k2 = 8

k2= 2 8

k2= 2 k = ± with k = ±

the equation is 2x2 + 2x + 1 = 0 roots is: but with

k = -, the equation is as this root is a –ve it will reject k = -, only answer is k = + only.

CAT-2005-Previous Years Paper Flashcard List

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