Previous Year Paper
CAT-2004-Previous Years Paper
If a man cycles at 10 km/h, then he arrives at a certain place at 1 pm If he cycles at 15 km/h, he will arrive at the same place at 11 am At what speed must he cycle to get there at noon?
When speed of the man = 10 km/h = and
When speed of the man = 15 km/h =
Equating the value of d : 10 × t = 15 × (t − 2) ⇒ t = 6 h
Finally desired speed = 12 km/h.