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CAT-2002-Previous Years Paper
If there are 10 positive real numbers n 1 < n2 < n3... < n10, How many triplets of these numbers (n1, n2, n3), (n2, n3, n4),…can be generated such that in each triplet the first number is always less than the second number, and the second number is always less than the third number?
Total possible arrangements = 10 × 9 × 8
Now 3 number can be arranged among themselves in 3! way = 6 ways
Given condition is satisfied by only 1 out of 6 ways hence, the required number of arrangements=