Previous Year Paper
CAT-2004-Previous Years Paper
In the figure shown below, chord ED is parallel to the diameter AC of the circle. If ∠CBE = 65o, then what is the value of ∠DEC?
∠B = 90° (Angles in semicircle)
Therefore ∠ABE = 90 – 65 = 25°
Also ∠ABE = ∠ACE (angel subtended by same arc AE)
Also ∠ACE = ∠CED [AC ||ED]
Therefore ∠CED = 25°