Loading....
Coupon Accepted Successfully!

Previous Year Paper

Open Flashcards

CAT-2004-Previous Years Paper

Question
31 out of 35
 

In the figure shown below, chord ED is parallel to the diameter AC of the circle. If CBE = 65o, then what is the value of DEC?



A 35°
B 55°
C 45°
D 25°

Ans. D

In ABC

B = 90° (Angles in semicircle)

Therefore ABE = 90 – 65 = 25°

Also ABE = ACE (angel subtended by same arc AE)

Also ACE = CED [AC ||ED]

Therefore CED = 25°

CAT-2004-Previous Years Paper Flashcard List

35 flashcards
1)
2)
3)
4)
5)
6)
7)
8)
9)
10)
11)
12)
13)
14)
15)
16)
17)
18)
19)
20)
21)
22)
23)
24)
25)
26)
27)
28)
29)
30)
31)
32)
33)
34)
35)