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Previous Year Paper

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CAT-2006-Previous Years Paper

Question
22 out of 25
 

Let f(x) = max (2x + 1, 3 – 4x), where x is any real number. Then the minimum possible value of f(x) is



A 1/3
B 1/2
C 2/3
D 4/3

E 5/3

Ans. E

To find out min of f(x) = max (2x + 1, 3 – 4x), we should be taking the point of intersection of (2x + 1) and (3 – 4x). [Since one of these equations is increasing and other one is decreasing]

2x + 1 = 3 – 4x, or, x = 1/3

2x + 1 = 3 – 4x = 5/3

Hence option (e) is the answer.

CAT-2006-Previous Years Paper Flashcard List

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