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CAT-2005-Previous Years Paper

Question
11 out of 30
 

Let n! = 1 × 2 × 3 ×... × n for integer n ≥ 1. If p = 1! + (2 × 2!) + (3 × 3!) + ... + (l0 × 10!), then p + 2 when divided by 11! leaves a remainder of



A 10
B 0
C 7
D 1

Ans. D

If p = 1! = 1

Then p + 2 = 3 when divided by 2! remainder will be 1.

If p = 1! + 2 × 2! = 5

Then p + 2 = 7 when divided by 3! remainder is still 1.

Hence, p=1!+(2×2!)+(3×3!)+…+ (10×10!)

When divided by 11! leaves remainder 1.

Hence, the remainder is 1.

CAT-2005-Previous Years Paper Flashcard List

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