Previous Year Paper
CAT-2003-Previous Years Paper
Let n (>1) be a composite integer such that √n is not an integer. Consider the following statements:
A: n has a perfect integer-valued divisor which is greater than 1 and less than
B: n has a perfect integer-valued divisor which is greater thanbut less than n
|A||Both A and B are false|
|B||A is true but B is false|
|C||A is false but B is true|
|D||Both A and B are true|
Let n = 6
Therefore, divisors of 6 are 1, 2, 3.
If we take 2 as divisor, then
Statement A is true
If we take 3 as divisor, then 6 > 3 > 2.4, i.e., n > 3 >
Therefore, statement B is true.