Previous Year Paper
CAT-2002-Previous Years Paper
On a straight road XY, 100 m long, five heavy stones are placed 2 m apart beginning at the end X. A worker, starting at X, has to transport all the stones to Y, by carrying only one stone at a time. The minimum distance he has to travel is
Every trip will need more than 180 m and there are trips. hence, the distance covered will be greater than 750 m for which there is only one option = 860.
For the first stone, he will cover 100 m.
For second, 200 − 4 = 196
For third, 200 − 8 = 192
For fourth, 200 − 12 = 188
For fifth, 200 − 16 = 184
Hence, the total distance = 860 m