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CAT-2004-Previous Years Paper

Question
7 out of 35
 

Suppose n is an integer such that the sum of digits on n is 2, and 1010< n <1011. The number of different values of n is



A 11
B 10
C 9
D 8

Ans. A

We have

(1) 1010< n <1011

(2) Sum of the digits for ‘n’ = 2 clearly

(n) min = 10000000001 (1 followed by 9 zeros and finally 1)

Obviously, we can form 10 such numbers by shifting ‘1’ by one place from right to left again and again. Again, there is another possibility for n

n = 20000000000

So finally: Number of different values for n = 10 + 1 = 11 answer.

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