Find the lowest number in an AP such that the sum of all the terms is 105 and greatest term is 6 times the least...??
Also it is given that
Also n/2*(a+l)= 105
[Where l is last term]
Now n/2*(a+6a)= 105
n/2*(7a)= 105 or n*a=30
Now , we will go by option if that is given.
Correct answer is 5, 10, 15....these 3's no. Are satisfy our condition.