Transitive Property

Since $\frac{1}{Q}$> 1 and 1 > 0, we know from the transitive property that $\frac{1}{Q}$ is positive.

Hence, Q is positive.

Therefore, we can multiply both sides of $\frac{1}{Q}$ > 1 by Q without reversing the inequality:

$QÂ·\frac{1}{Q}$> $1Â·Q$

Reducing yields

1 > Q

Multiplying both sides again by Q yields

Q > Q 2

Using the transitive property to combine the last two inequalities yields

1 > Q 2

Hence, column B is greater then column A.