How many milliliters of a solution having 10% alcohol should be added to a mixture of 48ml of pure water and 400ml solution having 40% alcohol to get a 25% alcohol solution
Let solution to be added =10x
Now acc to ques.. we hav 48ml of pure water n 160 ml of alchohal + 240 ml of water..which makes 288 ml water n 160 ml alcohal...
The sol to be added has 9x water n x amount of alcohal..
(160+x)/(288+9x+160+x) = 25/100....
Solve to get 10x =320