# Concept of Approximation

This is one of the easiest and high scoring portion. One needs to solve the questions of approximation by taking the nearest approximate values and mark the answers accordingly.

**Note:-** If it is given 3.009 then the approximate value is 3

If it is given 6.99 then the approximate value is 7

But if it is given 4.45 then we will take it 4.50, not 4 or 5.

Example-1

2959.85 Ã· 16.001 â€“ 34.99 = ?

- 160
- 150
- 140
- 180
- 170

Solution

? = 2959.85 Ã· 16.001 â€“ 34.99
â‰ˆ 2960 Ã· 16 â€“ 35
â‰ˆ 2960/16 â€“ 35
â‰ˆ 185 - 35
â‰ˆ 150

Hence, answer is (2).

Hence, answer is (2).

Example-2

(1702 Ã· 68) Ã— 136.05 = ?

- 3500
- 3550
- 3450
- 3400
- 3525

Solution

? = (1702 Ã· 68) Ã— 136.05
â‰ˆ (1700 Ã· 68) Ã— 136
â‰ˆ 3400

Hence answer is (d).

Hence answer is (d).

Example-3

16.5 x 2400 = 2/3 of ?

- 588
- 594
- 592
- 590
- 582

Solution

We know 16.5 % = 1/6(very closely)
Now the question is 1/6 x 2400 = 2/3 of ?
Answer is 600.
But we manipulated something which is smaller than the actual value so answer is smaller and closer to 600, just tick 594. This is the technique of accurate approximation.