**Question:**

If the HCF of (x^2+px-q) and (5x^2-3px-15q) is (x-3) then what will be the value of p and q?

Now, putting x=3 in x^2+px-q=0 we get

3p-q=-9----(1)

Again putting x=3 in 5x^2-3px-15q=0 we get

3p+5q=15----(2)

So, from (1) and (2) we get

p=-5/2 and q=3/2 ans.

P=-7/3,q=-2