If three squares are selected at random from chessboard, then the probability that they form the letter L is......??? A. 49/64 C 3 B. 196/64 C 3 C. 36/64 C 3 D. 98/64 C 3
Total number of ways to choose 3 squares is 64C3. Starting from the 1st square at upperleft corner of 1st row, there is only one way to choose thee remaining two squares from the second row adjacent to it such that they form the letter L and this is possible for all the 7 squares(excluding the 8th one) present in 1st row. Thus, it is 7 squares for one row. Similarly, for every 7 rows present(excluding the 8th one), it sums up to 7*7=49. The probability is 49/64C3.
If we select any three squres randomly we can make a "v" rather than a "L"
It is written in combination form from chapter permutations and combination.........read the options carefully and then ans.
Oh sorry I as was taking L up left and up right sorry and ans is -a)49 right or wrong
196 is total number of ways we can get L with adjacent squares. If required outcomes are not 196 then it must be greater than 196 as squares need not to be adjacent but there is no such opt. Is there really other answer
Wrong abhinav........pls dont underestimate it easily.......