In 6 hrs sita can make 4 more baskets than what geeta can in 4 hrs. If each worked at the rate that the other did , geeta can make 2 baskets less than sita in 2 hrs. What will b the equition????
Let's assume Sita makes 's' baskets in one hour and Geeta makes 'g' baskets in one hour.
From first condition,
6s = 4g + 4
From second condition,
2g = 2s - 2
Though the conditions are not solvable. If the rate of work is constant, the above two conditions can never happen because in first condition Sita is faster and in second Geeta is faster. This is contradictory.