# Motion of Charged Particle in Electric Field

**When a charged particle enters with an initial velocity at right angle to the uniform field**When a charged particle enters perpendicularly in an electric field, it describes a parabolic path as shown in Fig. 11.

**Fig. 11**

**Equation of trajectory:**Throughout the motion particle has uniform velocity along

*x*-axis and horizontal displacement (

*x*) is given by the equation

*x*=

*ut*.

Since the motion of the particle is accelerated along

*y*-axis, so .This is the equation of parabola which shows

*y*∝*x*^{2}.**Velocity at any instant:**At any instant

*t*,

*v*=

_{x}*u*and . So

**Fig. 12**

If

*β*is the angle made by*v*with*x*-axis, then