**Question:**

Let alpha and beta be the roots of equation px^2 + qx + r =0, p not equal to zero. If p, q, r are in A.P. and 1/alpha + 1/beta =4, then find the value of |alpha-beta| ???

Thanks __karthik__

This is a JEE mains 2014 question.

@Nilesh

Since p q and r are in AP therefore

(p+r)/2 =q

Also alpha+beta =

-q/p

Also, Alpha*beta =

r/p

Given|alpha-beta| =4

Therefore alpha-beta = root[(alpha+ beta)square-4alpha*beta]

Use the above eqns and do it.

Sorry its 2(root 13)/9

2(root 11)/7

Its easy

2root11/7

Watsapp me at 9757103805

Please give some hint i am stuck __inbetween__

|x| = 2√13/9

2*root17/9