## General Chemistry

### Equilibrium and Kinetics

**2 out of 13**

Based on the given data, what is the rate law of the following hypothetical reaction?

A | Rate = k [ Y ] |

B | Rate = k [ X ] [ Y ] |

C | Rate = k [ X ]^{2} [ Y ] |

D | Rate = k [ X ] [ Y ]^{2} |

**Ans. C**From the given equation, we can write the general form of the rate as:

Rate = k [X]^{m} [Y]^{n}

Our next step is to find m and n using the given information. Examining the first and the second experiments shows that the concentration of X is kept constant, but the concentration of Y is doubled. When the concentration of Y is doubled, the rate also is doubled. So the order (n) with respect to Y is 1. Now compare experiments 2 and 3. In experiments 2 and 3, the concentration of Y is kept constant, but the concentration of X is doubled. This time, the rate is quadrupled. Hence, the order (m) with respect to X should be 2. So the correct expression is Rate = k [ X ]^{2} [ Y ].

##
Equilibrium and Kinetics Flashcard List

**13**flashcards

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