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General Chemistry

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Equilibrium and Kinetics

Question
2 out of 13
 

Based on the given data, what is the rate law of the following hypothetical reaction?

image\27402 ch 11 Q 2.png

image\15208 ch 11 Q 2.png



A Rate = k [ Y ]
B Rate = k [ X ] [ Y ]
C Rate = k [ X ]2 [ Y ]
D Rate = k [ X ] [ Y ]2
Ans. C From the given equation, we can write the general form of the rate as:

Rate = k [X]m [Y]n

Our next step is to find m and n using the given information. Examining the first and the second experiments shows that the concentration of X is kept constant, but the concentration of Y is doubled. When the concentration of Y is doubled, the rate also is doubled. So the order (n) with respect to Y is 1. Now compare experiments 2 and 3. In experiments 2 and 3, the concentration of Y is kept constant, but the concentration of X is doubled. This time, the rate is quadrupled. Hence, the order (m) with respect to X should be 2. So the correct expression is Rate = k [ X ]2 [ Y ].

Equilibrium and Kinetics Flashcard List

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