## Biological Sciences

### Evolution

**5 out of 6**

Cystic fibrosis, a recessive genetic disease, occurs in a particular population in approximately 1 of every 2,000 births. What is the frequency of carriers in this population?

A | 0.0224 |

B | 0.9776 |

C | 0.0219 |

D | 0.0438 |

**Ans. D**

You are given the frequency of affected individuals, 1 in 2,000, or 0.0005. This is the frequency of the genotype *aa*, which is equal to *q*^{2}. Therefore, *q* is equal to 0.0224. Since we know *q*, we also know *p* (1 – *q* = 0.9776). In a population, carriers are heterozygotes, individuals who carry the allele but are not affected by it. The formula to calculate the frequency of heterozygotes is 2*pq*. therefore, the frequency of carriers in this population is 0.0438.

##
Evolution Flashcard List

**6**flashcards

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