Non competitive inhibitor exhibits all except ? a) km constant b) vmax decrease c) vmax constant d) none of the above .
Ans is c ...because in non competitive inhibition it binds at diff.site and alters the functioning site so aft. Increasing the substrate concentration ,the action can't be achieved normal...so vmax is deceased
Its c. Bcoz in non competitive inhibition the enzyme blocks d site of attachment of substrate. So v max should be decreased...
Can anyone give explaination