**Question:**

The ratio of areas of a regular hexagon and an equilateral triangle having same parimeter is.... 1)2:3 2)6:1 3)3:2 4)1:6

Ya akhlesh you did it very nicly.....

Explaination:-

Let the measure of each side of hexagon be x.

So, perimeter of hexagon=perimeter of the triangle=6x

Each side of triangle=6x/3=2x

Hence, required ratio=

6×√3/4×x^2:√3/4×(2x)^2

=3:2

If doubt, post.

It it ques of chsl 2011

But i have solved ans of this ques which proves 3:2

__4__

If you dont have reason. Dont ever __deny__

Explain it..

You say __how__

No....mukesh...

3:__4__