**Question:**

The value of lim x-> 0 xsin (1/x) is?

As it is applicable in 0/0 formm

See l hopital cant be used

__1__

Use l hopital __rule__

__0__

Therefore. Lim x->0 Sin x^-1 / x^-1 =1

As we know lim x->0 sin x /x =1

1 .... Actually slightly less than 1.

Give me proof.