Wurtz reaction differs If we take two different alkyl halides For eg. We take equal moles of bromomethane and bromoethane with required sodium then what would be major product?
Sorry for spelling errors I meant methy free radical is less stable then ethyl so two ethyl feee radical combine to orm butane
Butane cuz wurtz proceed via free radical mechanism and 2degree free rabible is stable then 1 degree ie methyl free rable is lesss stanle then ethyl so teo eth6l free radicals will combine to rtom butane
According to u Aaditya....ethane can also be answer?????so....
Firstly if we use two different alkyl halides in wurtz reaction then the major product will be the most stable self coupled compound........the answer for this question is butane not propane
Y propane.....explanation needed
Major product will be propane.
Butane also is a symmetrical and can be formed by 2 bromo butane and 2 na so que. Still arise
Ethane as wurtz reaction forms symmetrical alkanes and bromine will go and get attached to the sodium