from a ground point, the angle of elevation of a building is found to be such that Tangent is 5/12. after walking 192 m towards the building, thangent changes to 3/4. find height of the building.
Could u plz explain ur answer
Height of the building is 180m.
In a right angled triangle , the
Tan(angle) = opposite side/adjacent side.
From the given point :
Height / Distance = Tan(angle) = 5/12
After we move 192m towards the building
Height / Distance-192 = Tan(new angle) = 3/4
On solving both the equations , we get the height as well as the distance.