**Question:**

"A" alone would take 32 days more to complete a work than if both " A and B" would together. If "B" worked alone, he took 8 days more to complete the work than when " A and B" worked together. What time would they take if both " A and B " work together ? A) 28 B) 24 C) 20 D) 16 E) 12

Let A+B can do the whole work in x days

So, one day work of A+B =1/x ...(1)

According to question A can take 32 days extra then A+B

So,equation is

A=x+32

One day work of A is

1/x+32..(2)

According to question B can take 8 days extra then A+B

B=x+8

One day work of B

1/x+8...(3)

From eq

Eq 1=eq 2+eq 3

1/x=1/x+32. + 1/x+8

Solve it you get

X=16

That is the working days of A+B together o complete the work.

Explain clearly??

16

A alone take X+32days

B alone take X+8days

We found 1/(x+32)+1(x+8)=1/x

X=17

__16__

16 __DAYS__

__16__

X=16

16 dayd