**Question:**

"What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?

A. 90

B. 95

C. 100

D. 105

E. 110

Py! AND __LAZY__

D

__C__

__C__

(10+100)÷__2__

C

Average={10+20+30+40+50+60+70+80+90+100+110+120+130+140+150+160+170+180+190}/19=100(C)

__C__

B

And n=20

So, summation on multiple/n

=1900/20

=__95__