**Question:**

By walking at 3/4 of his usual speed,a man reaches his office 20 min later than his usual time.The usual time taken to reach his office is Pls giv the ans wit xplanatn

60

3/(4-3)×20=60

He decreases his speed 1/3.so if 1/3 =20 min then 1=20×3=60 min

Its 60 min

equate distance

3/4 s *(t+20)=s*t

t refers to time

s refers to speed

60 mins

60mins

60 minutes , distance/time is speed, here distance is constant , so (d/t=s) s1*t1=s2*__t2__

1 hour 20 min