**Question:**

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age? A. 2 times B. 2 1 times 2 C. 2 3 times 4 D. 3 times

**Answer-1**

2 times :

age of ronit : 16yrs

age of father : 48 yrs.

let age of ronit be x.

then father's age will be 3x.

after 8 yrs :

ronit age = x+8;

father's age = 3x+8;

now as per eq

2.5(x+8)=3x+8

x=16

age of ronit : 16yrs

age of father : 48 yrs.

let age of ronit be x.

then father's age will be 3x.

after 8 yrs :

ronit age = x+8;

father's age = 3x+8;

now as per eq

2.5(x+8)=3x+8

x=16