## Reasoning

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### Ranking and Direction Test

Question

**8 out of 25**

A person starts from a point A and travels 3 km eastwards to B and then turns left and travels thrice that distance to reach C. he again turns left and travels five times the distance he covered between A and B and reaches his destination D. the shortest distance between the starting point and the destination is

A | 12 km |

B | 15 km |

C | 16 km |

D | 18 km |

E | None of these |

**Ans. B**The movements of the person are as shown in figure.

Clearly, AB = 3 km; BC = 3AB = (3 × 3) km = 9 km; CD = 5 AB = (5 × 3) km = 15 km.

Draw AE _ CD. Then, CE = AB = 3 km and AE = BC = 9 km.

DE = (CD – CE) = (15 – 3) km = 12 km. In ∆AED, AD^{2} = AE^{2} + DE^{2} AD = √9^{2} + 12^{2} km = √225 km = 15 km. So, required distance = AD = 15 km.

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Ranking and Direction Test Flashcard List

**25**flashcards

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