**Question:**

If the average (arithmetic mean) of 5 consecutive integers is 11, what is the sum of the least and greatest of the 5 integers?

1. 23

2. 22

3. 21

4. 20

5. 19

The arithmetic mean is sum of all these nos divided by 5 which gives

a+2d=11

Now first term +last term gives

2a+4d which is equal to 2*11=22

22

Therefore, if a1, a2, a3, a4 and a5 are the five consecutive integers, then a3 = 11

Hence, a1 = 9 and a5 = 13

Sum of the least and the greatest integer = a1 + a5 = 9 + 13 = 22.

Choice 2