Length of rectangle exceeds its breadth by 7 cm. If the length & breadth is decreased by 4 cm & 3 cm, then the area of the new rectangle is same as the area of the original. What will be the perimeter of the original rectangle? Plzz explain how to crack..
Even I think question is incorrect. Found the question in previous IBPS SO paper. Answer happends to be 50. I don't have any idea how the answer is 50...
Respectively lagaana bhool gya chore
Question is wrong...length goes into minus...lol
@ Kulajeet bro, I think the qstn is wrng , because if both the length and breadth is reduced, area will not remain the same. It will be reduced.
Qstn should have been like this
1.if length is decreased by 4 & breadth is incrsd by 3.
2. If length is incrsd by 4 & breadth is decreased by 3.
Ans. l=40,b=33, p=146 .
Let the width is x and then length is x+7 then the area A=x(x+7)
Then reducing length and width by 4 and 3 i.e
(x+7)-4 and x-3 the new area becomes A=(x+3)(x-3)
Thn solve x(x+7)=(x+3)(x-3)