**Question:**

The average of the terms of the given series (152, 150, 148, 146, 144__) is 126, then the total number of terms in this series will be...??

A/q

(a+l)/2=126

(152+l)=252

So, l=100

Now, n=(l~a)d+1

=(152-100)/2+1

=27.

27...

Okkk...thanx arun

1st term + last term / 2 = __average__

Arun yh 100 kaise aaye yh smajh ni aaya..

a + l / 2 = 126

152 + l / 2 = 126

l = last term = 100

Using A.P

l = a × (n-1) × d

n = __27__

Bt aapke according yh logic hr kisi m fit baith rha h...(first digit-average no. + 1)...

Thanx 4 it..

Sorry Asel bt yh logic smajh ni aaya..n 126 to 14 no. Pr h...n digit ka difference series no. Kaise ho skti h...

Anyways thanx __4__ explain it....

Difference between 152 and126 is 26. In the series 152, 150.... two is getting decreased ... hence above 126 there should 13 numbers.. yo get 126 as average we should have 13 numbers after 126 in that series.. including 126 , there 27 numbers..

Yes..asel explain Plzzzz