a car of 3000 kg travels a flat road at constant speed of 20 m/s. the friction on the tire has a coefficient of 0.5. what is the net force acting on the car?
So actually what is answer
No force is acting as velocity is constant
0.00 N the lose due to friction is given to the car by the engine.... But no NET force
Since the body is moving with constant speed there no acceleration produced and hence net force equals to frictional force which is 3000×10×0.5=15000N
Answer is 0N
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