indefinite integral of dx/(Secx+tanx)
na its wrong way
and this is not helping
it will nt be 1+vosx even in that sum...it would be 1+sinxcosx
Oh...sorry...the solution is for dx/cosec x+ cosx.
.but its of same type. ..hope u can figure it out
Write sec x as 1/cos x..take lcm nd ur question becomes sinx dx/1+cosx..
Take 1+cosx as t...dt=-sinx...
Now question becomes-dt/t = ln|1+cosx| +c
sry the sum is dx/(secx+sinx)